Question

The ninth term of 1/4, 3, 36, 432

Answer 1

Given the sequence:

$\frac{1}{4},3,36,432$

This sequence is a geometric sequence, where the first term is 1/4, and the common ratio is 12:

$\begin{gathered} a_1=\frac{1}{4} \\ a_n=\frac{1}{4}\cdot12^{n-1} \end{gathered}$

The ninth term is:

$\begin{gathered} a_9=\frac{1}{4}\cdot12^{9-1}=\frac{1}{4}\cdot12^8 \\ \therefore a_9=107495424 \end{gathered}$