Question

O GEOMETRYIIIPerimeter involving rectangles and circlesA rectangular paperboard measuring 32 in long and 26 in wide has a semicircle cut out of it, as shown below. What is the perimremains after the semicircle is removed? (Use the value 3.14 for it, and do not round your answer. Be sure to include the correctinin?26 inХ532 in

Answer 1

First, we compute the perimeter of the semicircle:

$\begin{gathered} P_s=\frac{1}{2}(2\pi r) \\ \text{Where r is the radius of the semicircle, in this case r=}13\text{ in, substituting r we get:} \\ P_s=\pi(13\text{ in)=40.82 in} \end{gathered}$

Finally, we add the lengths of the remaining sides with the perimeter of the semicircle:

$P=32in+32in+26in+40.82in=130.82in$

Answer: 130.82 in