A pyramid has a rectangular base of length (2x + 1)cm and width xcm. it also has a perpendicular height of 18cm. the volume of the pyramid is 90 cm?. given that the volume of a pyramid is one third of the area of the base multiplied by the perpendicular height, find the dimensions of the base of the pyramid.

Respuesta :

The dimensions of the base of the pyramid are width: 5/2cm and length: 8.5cm.

What is a pyramid?

A three-dimensional shape is a pyramid. Its base is a flat polygon. The other faces, referred to as lateral faces, are all triangles.

The number of sides on its base is equal to the number of lateral faces.

The volume of a pyramid?

The volume of a pyramid is 1/3 base area × height.

What is a Quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x ax2+bx+c=0. with a ≠ 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

Here, we have

volume of a pyramid = 90cm

Length = (2x+1)

Width = x

Perpendicular height = 18cm

Then by the volume of a pyramid, we get

Area of the base = (2x + 1)x = (2x² +x) (cm²)

Volume of the pyramid = 1/3×(2x² +x)×18 = 90

                                        = 12x² + 6x = 90

                                        = 2x² + x - 15 = 0

                                        =  (2x-5)(x+3)

                                         x = 5/2

Length=3(5/2)+1

Length=7.5+1

Length=8.5cm

Hence, the dimensions of the base of the pyramid are: Width 5/2cm ; Length 8.5cm.

To learn more about the volume of a pyramid from the given link

https://brainly.com/question/29021848

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