we know that
The simple interest formula is equal to
[tex]A=P(1+rt)[/tex]
[tex]A=P\mleft(1+rt\mright)[/tex]where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
step 1
Find out the interest in one month
so
we have
P=$3,500
r=4.8%=4.8/100=0.048
t=1 month=1/12 years
substitute in the formula
[tex]\begin{gathered} A=3,500(1+0.048\cdot\frac{1}{12}) \\ A=\$3,514 \end{gathered}[/tex]that means
the interest is equal to
I=A-P
I=3,514-3,500=$14
the answer part a is
Yes, the poster can correctly say, "Open an account of $3,500 and earn at least $10 interest in 1 month!"
Part b
Find out the principal needeed to earn $10 in interest the first month\
we have
P=?
r=0.048
t=1/12 years
I=$10
the formula of interest is equal to
[tex]I=P(rt)[/tex]substitute
[tex]\begin{gathered} 10=P(0.048\cdot\frac{1}{12}) \\ P=\$2,500 \end{gathered}[/tex]therefore
teh answer part b is $2,500