Consider the following parametric equations:x = V1 – 2 and y = 1 + 3Step 1 of 2: Eliminate the parameter t. Please write your answer in simplest form solved for y.

Answer:
The equations are given below as
[tex]\begin{gathered} x=\sqrt{t-2}........(1) \\ y=t+3......(2) \end{gathered}[/tex]Step 1:
Make t the subject of the formula from equation (1)
[tex]\begin{gathered} x=\sqrt{t-2} \\ square\text{ both sides} \\ x^2=(\sqrt{t-2)^2} \\ x^2=t-2 \\ add\text{ 2 to both sides, we will have} \\ x^2+2=t-2+2 \\ t=x^2+2.....(2) \end{gathered}[/tex]Step 2:
Substitute the equation (3) in equation (2)\
[tex]\begin{gathered} y=t+3......(3) \\ t=x^2+2 \\ y=x^2+2+3 \\ y=x^2+5 \end{gathered}[/tex]Hence,
The final equation for y after eliminating t is
[tex]y=x^2+5[/tex]