Answer:
7 m³
Explanation:
At a constant temperature, we have the following relationship between volume and pressure:
[tex]P_2V_2=P_1V_1_{}[/tex]Where P is the pressure and V is the volume. So, we can solve for the final volume V2 as:
[tex]V_2=\frac{P_1V_1}{P_2}[/tex]Replacing P1 = 4 atm, V1 = 10.5 m³, and P2 = 6 atm, we get:
[tex]V_2=\frac{4\text{atm}\cdot10.5m^3}{6atm}=7m^3[/tex]Therefore, the final volume of the lungs will be 7 m³