Given:
n = 1 , 2 , 3, 4, 5
f(n) = 1, 3, 5 , 7, 9
Let's find the common differnce,
9 - 7 = 7 -5 = 5 - 3 = 3 - 1 = 2
The common diffrence is 2.
The explicit rule is:
f(n) = 1 + 2(n - 1)
The recursive rule is:
[tex]a_n=a_{n-1}+2_{}[/tex]ANSWER:
f(1) = 1
d = 2
E : f(n) = 1 + 2(n - 1)
[tex]\begin{gathered} R\colon_{} \\ \mleft\{\begin{aligned}a(1)=1 \\ a_n=a_{n-1}+2\end{aligned}\mright. \end{gathered}[/tex]