Question

Given P(A) = 0.68, P(B) = 0.5 and P(A|B) = 0.91, find the value ofP(An B), rounding to the nearest thousandth, if necessary.

Answer 1

Remember that

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Thereby,

$P(A\cap B)=P(A|B)\cdot P(B)$

Using the data given,

$P(A\cap B)=0.455$