Distribute the negative to the second trinomial and simplify by adding like terms. We get the following:
[tex]\begin{gathered} 7x^{2}-5x+3-(2x^{2}+7x-4) \\ =7x^2-5x+3-2x^2-7x+4 \\ =7x^2-2x^2-5x-7x+3+4 \\ =5x^2-12x+7 \\ \\ \text{Therefore,} \\ 7x^2-5x+3-(2x^2+7x-4)=5x^2-12x+7 \end{gathered}[/tex]