The expected value is given by:
[tex]E(x)=\sum ^{}_{}xP(x)[/tex]In this case we have:
[tex]\begin{gathered} E(x)=430(\frac{1}{250})+290(\frac{1}{250})+190(\frac{1}{250})+130(\frac{1}{250}) \\ =4.16 \end{gathered}[/tex]Therefore the expected payoff is $4.16