Explanation
Question 10
We are asked to write the quadratic eqation that has the solutions of x=3 and x =-7
To do so, we will make use of
[tex]y=x^2-(sum\text{ of roots})x+product\text{ of roots}[/tex]So we will follow the steps below
[tex]\begin{gathered} Sum\text{ of roots = 3+}-7=-4 \\ product\text{ of roots =3\lparen-7\rparen=-21} \end{gathered}[/tex]substituting the above, we will have
[tex]\begin{gathered} x^2-(-4)x+(-21)=0 \\ \\ x^2+4x-21=0 \end{gathered}[/tex]Therefore, the quadratic equation is
[tex]x^2+4x-21[/tex]