Question

Verify that’s the ordered pair name in part(a) is a solution to 2y+x=12

Answer 1

PART A

To find the solutions to the system, we can multiply the second equation by -2

$\begin{cases}2y+x=12 \\ -2y=-\frac{5}{3}x+4\end{cases}$

Then, we combine the equations and solve for y

$\begin{gathered} x=12-\frac{5}{3}x+4 \\ x+\frac{5}{3}x=16 \\ \frac{3x+5x}{3}=16 \\ 8x=16\cdot3 \\ x=\frac{48}{8} \\ x=6 \end{gathered}$

Now, we find y using x-value

$\begin{gathered} 2y+x=12 \\ 2y+6=12 \\ 2y=12-6 \\ y=\frac{6}{2} \\ y=3 \end{gathered}$

Hence, the ordered pair where the graphs intersect is (6,3).

Part B.

To verify that the point (6,3) is a solution of 2y+x = 12, we just have to replace it

$\begin{gathered} 2\cdot3+6=12 \\ 6+6=12 \\ 12=12 \end{gathered}$

As you can observe, it satisfies the equation, so it's a solution to it.

Part C.

To verify that the point (6,3) is a solution of the second equation, we just have to replace it

$\begin{gathered} y=\frac{5}{6}x-2 \\ 3=\frac{5}{6}\cdot6-2 \\ 3=5-2 \\ 3=3 \end{gathered}$

Hence, the point is a solution to the second equation too.

PART D.

Point (4,4) couldn't be a solution of the system because it has a unique solution, which is (6,3). Additionally, the point (4,4) only satisfies the first equation but not the second one, and the solution must be a solution to both equations.