ANSWER
[tex]2\cdot10^3V[/tex]EXPLANATION
To find the potential difference between the two points, we have to apply the relationship between work done by an electric field and potential difference:
[tex]W=q\Delta V[/tex]where q = charge
ΔV = potential difference
Hence, the potential difference is:
[tex]\begin{gathered} \Delta V=\frac{W}{q} \\ \Delta V=\frac{2\cdot10^3}{1} \\ \Delta V=2\cdot10^3V=2kV \end{gathered}[/tex]That is the answer.