[tex]\begin{gathered} \text{the straight line equations is given by: y = mx +b} \\ \text{where m is the slope and also represens the rate. This means that Henry rates is 0.9.} \\ \\ \text{Now, we ne}ed\text{ the slope from the Clark's graph in order to compare the rates. A good point for that is that the graphs pass} \\ \text{throght the point (5,6)} \end{gathered}[/tex][tex]\begin{gathered} \text{pass throght the points (5,6) and (0,0), then the slope is} \\ m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-0}{5-0}=\frac{6}{5} \\ m=1.2 \\ \text{where (x}_2,y_2)=(5,6)\text{ and (x}_1,y_1)=(0,0) \end{gathered}[/tex][tex]\text{then, Henrys rate is 0.9 and Clarks rate is 1.2. Hence Clarks hikes faster}[/tex]
