Calculate the gravitational force of a 90.0 kgperson who is standing on the planet next toyour name. Write the given, equation,substitution, and final answer in 3 significantfigures into your notebook.PlanetaryDataPlanetMass (kilograms) Radius(meters)6.39 x 10233.39 x 106Mars

Respuesta :

Given data:

Mass of the person;

[tex]m=90.0\text{ kg}[/tex]

Mass of the planet;

[tex]M=6.39\times10^{23}\text{ kg}[/tex]

Radius of the planet;

[tex]r=3.39\times10^6\text{ m}[/tex]

The gravitational force is given as,

[tex]F=\frac{GMm}{r^2}[/tex]

Here, is universal gravitational constant.

Substituting all known values,

[tex]\begin{gathered} F=\frac{6.67\times10^{-11}\times6.39\times10^{23}\times90}{(3.39\times10^6)^2} \\ =333.787\text{ N} \end{gathered}[/tex]

Therefore, the gravitational force experinced by the person is 333.787 N.

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