The first thing we have to do is find the equations that describe the problem:
• Two certificates of deposit pay interest at rates that differ by ,2%,.
[tex]\lvert i_2-i_1\rvert=2[/tex]• Money invested ,for one year in the first CD ,earns, ,$120, interest.
[tex]MI\cdot i_1=120[/tex]• The same principal invested i,n the other CD earns , $160
[tex]MI\cdot i_2=160[/tex]We can see that we have the same money invested so we can match it to find another equation that helps us clear the interests:
[tex]\begin{gathered} MI_{}=\frac{120}{i_1} \\ MI=\frac{160}{i_2} \\ \frac{160}{i_2}=\frac{120}{i_1} \\ 160\cdot i_1=120\cdot i_2 \\ i_1=\frac{120}{160}i_2 \\ i_1=\frac{3}{4}i_2 \end{gathered}[/tex]With the equation cleared for interest 1, we plug into the first equation to find interest 2
[tex]\begin{gathered} i_2-\frac{3}{4}i_2=2 \\ \frac{1}{4}i_2=2 \\ i_2=2\cdot4 \\ i_2=8 \end{gathered}[/tex]Now we calculate the value of interest 1 using the first equation replacing the calculated value of interest 2
[tex]\begin{gathered} 8-i_1=2 \\ i_1=8-2 \\ i_1=6 \end{gathered}[/tex]So the 2 interest rates are
• smaller value:, ,6%
• larger value:, , 8%