Question

Using the given equation, (a) find the intercepts of its graph and(b) use the intercepts to graph the equation.

Answer 1

we have the equation

4x+3y=12

this is a linear equation

step 1

Find out the y-intercept

(value of y when the value of x is zero)

For x=0

4(0)+3y=12

3y=12

y=4

the y-intercept is the point (0,4)

step 2

Find the x-intercept

(value of x when the value of y is zero)

For y=0

4x+3(0)=12

4x=12

x=3

the x-intercept is the point (3,0)

step 3

graph the equation

plots the intercepts, join them to draw the line

see the attached figure