Question

Two resistors having values of 6 Ω and 12 Ω are connected in parallel to a 36 V battery. Find the power dissipated by the 6 Ω resistor.Group of answer choices216 W138 W189 W167 W

Answer 1

216 W

Explanation:

Formula:

Power dissipated = Voltage squared / Resitor

P = V^2 / R

Data:

V = 36 => V^2 = 1,296 V

Resistor = 6 ohm

Solution:

P = 1,296 / 6 = 216 W