Use the following formulas to find the vectorial components of the tension force.
[tex]\begin{gathered} T_x=T\cdot\cos \theta \\ T_y=T\cdot\sin \theta \end{gathered}[/tex]Where T = 350 N and theta = 51.
[tex]\begin{gathered} T_x=350N\cdot\cos 51\approx220.26N \\ T_y=350N\cdot\sin 51\approx272N \end{gathered}[/tex]Therefore, the horizontal component of the tension force is 220.26 N, and the vertical component of the tension force is 272 N.