EXPLANATION
Given the expression 7 + √3, the conjugate is as follows:
[tex]\text{Conjugate: 7-}\sqrt[]{3}[/tex][tex]\text{Product:}(7+\sqrt[]{3})(7-\sqrt[]{3})=49-7\sqrt[]{3}+7\sqrt[]{3}-3=49-3=46[/tex]Hence, the conjugate is 7 - √3 and the product 46.