Answer:
A. 2.03
Step-by-step explanation:
Formula.
[tex]h(t)=-4.9t^2\text{ + 6t + 8}[/tex]When h(t) = 0 means that the ball is on the ground.
So, we equal the equation to 0, and then we clear t to find it.
[tex]0=-4.9t^2\text{ + 6t + 8}[/tex]To solve t we have to use the quadratic formula.
[tex]x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]a = -4.9
b = 6
c = 8
[tex]x_1=\text{ }\frac{-6-\sqrt[]{6^2-4\cdot-4.9\cdot8}}{2\cdot-4.9}\text{ }[/tex][tex]x_1=\frac{-6-\sqrt[]{13.88}}{-9.8}=2.03_{}s[/tex]Then x2
[tex]x_2=\frac{-6+\sqrt[]{6^2-4\cdot-4.9\cdot8}}{2\cdot-4.9}[/tex][tex]x_2=\text{ }\frac{-6\text{ + }\sqrt[]{13.88}}{9.8}=\text{ -0.80 s}[/tex]x2 It is not possible because time cannot be negative.