Given:
• White light:
n = 1.00
Angle, θ = 40.00°
• Red light:
n = 1.520
• Violet light:
n = 1.538
Let's find the difference in the refracted angles for red light an violet light.
To find the refracted angle for each light, apply the formula:
[tex]n_1sin\theta_1=n_2sin\theta_2[/tex]Thus, we have the following:
• Red light
[tex]\begin{gathered} n_wsin\theta_w=n_rsin\theta_r \\ \\ \theta_r=sin^{-1}(\frac{n_wsin\theta_w}{n_r}) \\ \\ \theta_r=sin^{-1}(\frac{1.00sin40}{1.520}) \\ \\ \theta_r=sin^{-1}(0.4228866) \\ \\ \theta_r=25.02^o \end{gathered}[/tex]The refracted angle for red light is 25.02°.
• Violet light.
We have:
[tex]\begin{gathered} \theta_v=sin^{-1}(\frac{1.00sin40.00}{1.538}) \\ \\ \theta_v=sin^{-1}(0.4179373) \\ \\ \theta_v=24.70^o \end{gathered}[/tex]The refracted angle for violet light is 24.70°.
The difference between the refracted angles will be:
[tex]\begin{gathered} \theta=\theta_r-\theta_v \\ \\ \theta=25.02^0-24.70^o \\ \\ \theta=0.32^0 \end{gathered}[/tex]Therefore, the difference in the refracted angles for red light and violet light is 0.32°.
• ANSWER:
0.32°