The average of the scores = sum/number
The scores are 88, 89, 91, 95
Their sum = 88 + 89 + 91 + 95 = 363
Let the score of the 5th quiz is x
Then the sum of the 5 quizzes = x + 363
Then the average of the 5 quizzes is
[tex]A=\frac{x+363}{5}[/tex]We need an average of at least 90, then
At least means greater than or equal
[tex]\therefore A\ge90[/tex]Substitute A by its value above
[tex]\therefore\frac{x+363}{5}\ge90[/tex]To solve it, multiply both sides by 5 to cancel the denominator on the left side
[tex]\begin{gathered} \because x+363\ge5\times90 \\ \therefore x+363\ge450 \end{gathered}[/tex]Subtract 363 from both sides to find x
[tex]\begin{gathered} \because x+363-363\ge450-363 \\ \therefore x\ge87 \end{gathered}[/tex]