Question

one fruit punch has 40% fruit juice and another is 10% fruit juice. How much of the 40% punch should be mixed with 10 gallons of the 10% punch to create fruit punch that is 25% fruit juice?

Answer 1

One fruit punch = 40% fruit juice

Another has = 10% fruit juice

let the amount of the 40% to be mixed be X

$\begin{gathered} \frac{40}{100}\times X\text{ +}\frac{10}{100}\times10\text{ =}\frac{25}{100}(X+10) \\ \frac{40X}{100}+\frac{100}{100}\text{ = }\frac{25(X+10)}{100} \\ \text{ }40X+100=25X+250 \\ collectingliketerms,wehave\text{.} \\ 15X=150 \\ X=10\text{gallons} \end{gathered}$$undefined$