hwo do we do part b its 3 parts only

Given :
[tex]y=4+\frac{4}{u}[/tex]Find: differentiation of y with respect to u
Explanation:
[tex]\begin{gathered} y=4+\frac{4}{u} \\ \frac{dy}{du}=0-\frac{4}{u^2} \\ \frac{dy}{du}=\frac{-4}{u^2} \end{gathered}[/tex]Final answer:
[tex]\frac{dy}{du}=\frac{-4}{u^2}[/tex]