Respuesta :

Given:

Hypotenuse = x

Angle = 30

Base = sqr root 3

Find -: The value of "x" and "y" is:

Sol:

Use trigonometric property then:

[tex]\cos\theta=\frac{\text{ Base}}{\text{ Hypotenuse}}[/tex]

[tex]\begin{gathered} \cos30=\frac{\sqrt{3}}{x} \\ \\ \frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{x} \\ \\ x=\frac{2\sqrt{3}}{\sqrt{3}} \\ \\ x=2 \end{gathered}[/tex]

For the value of "y" is:

[tex]\begin{gathered} \sin\theta=\frac{\text{ Perpendicular}}{\text{ Hypotenuse }} \\ \\ \sin30=\frac{y}{x} \\ \\ \frac{1}{2}=\frac{y}{2} \\ \\ y=\frac{2}{2} \\ \\ y=1 \end{gathered}[/tex]

So the value of y is 1

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