Question

Find the roots of the quadratic equation written in factored form below.(x + 6) (x – 3) = 0

Answer 1

The quadratic equation has already been factored as (x+6)(x-3) =0

The roots hence are the values of x that makes the equation hold

Therefore,

$\begin{gathered} x+6=0 \\ x=\text{ -6} \\ or \\ x-3=0 \\ x=\text{ 3} \\ so\text{ x = -6 or 3} \end{gathered}$

The roots of the equations are -6 or 3

Check

$\begin{gathered} We\text{ substitute independently, if x = -6 then} \\ (-6+6)(-6-3)=0_{} \\ \text{Hence, x=-6 holds} \\ \text{if x = 3} \\ (3+3)(3-3)=0 \\ 0=0 \\ \text{Hence x = 3 also holds} \end{gathered}$