Respuesta :

the decay factor is 0.4

Explanation:

The model: y = 4520(0.6)​

Using the exponential decay formula:

[tex]\begin{gathered} y=a(1-r)^x \\ y\text{ = final amount} \\ a\text{ = initial amount} \\ r\text{ = decay factor} \\ x\text{ = amount of time} \end{gathered}[/tex]

Comparing both equations:

y = y

a = 4520

(1 - r) = (0.6)

1 - r = 0.6

1 - 0.6 = r

r = 0.4

Hence, the decay factor is 0.4

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