Question

Question 2 If u +t=8 and u-t= 3. what is the value of u squared minus t squared

Answer 1

Explanation:

'u squared minus t squared' is u²-t².

If we use the difference of two squares theorem we can write it as:

$u^2-t^2=(u+t)(u-t)$

We have that

• u + t = 8

,

• u - t = 3

So u squared minus t squared is:

$u^2-t^2=(u+t)(u-t)=(8)(3)=24$

Answer:

The value of u squared minus t squared is 24