Question

If ABCD is dilated by a factor of, thecoordinate of C' would be:

Answer 1

Recall that a dilation by a factor of k, transforms the point (x,y) as follows:

$(x,y)\rightarrow(kx,ky).$

Now, the coordinates of point C are:

$C=(2,4).$

Therefore, after the dilation, the coordinates of C' are:

$C^{\prime}=(\frac{1}{2}(2),\frac{1}{2}(4)).$

Simplifying the above result, you get:

$C^{\prime}=(1,2).$

Answer:

$C^{\prime}=(1,2).$