Question

If 15.8 mL of 7.5 M HCI is used to make a 743.9 mL aqueous solution, what is the molarity of the dilute solution?O a. 0.16O b. 350O c. 530O d. 14

Answer 1

ANSWER

The final concentration of the solution is 0.16M

EXPLANATION

Given that;

The initial concentration of the solution is 7.5 M

The initial volume of the solution is 15.8mL

The final volume of the solution is 743.9mL

Follow the steps below to find the final concentration of the solution

Step 1; Apply the dilution formula

$\text{ C1 }\times\text{ V1 = C2 }\times\text{ V2}$

Step 2; Substitute the given data into the above formula

$\begin{gathered} \text{ 15.8 }\times\text{ 7.5 = C2 }\times\text{ 743.9} \\ \text{ 118.5 = 743.9 }\times\text{ C2} \\ \text{ Divide both sides by 743.9} \\ \text{ }\frac{\text{ 118.5}}{\text{ 743.9}}\text{ = C2} \\ \\ \text{ C2 = 0.16M} \end{gathered}$

Therefore, the final concentration of the solution is 0.16M

Hence, option A is the correct answer