1. In the isosceles ABC shown below, Band Care base angles. If m ABC={93-73)"andZACB-3x+23), find the value of x? Then find the measure of one base angle?АBСMeasure of 1 base angle =

As per given by the question,
There are given that,
The measure angle is,
[tex]m\angle ABC=(9x-73)^{\circ}[/tex]And,
[tex]m\angle ACB=(3x+23)^{\circ}[/tex]Now,
From properties of isoscales triangle,
The two angles opposite to the equal sides are equal.
So,
[tex]\angle B=\angle C[/tex]From the given triangle;
[tex]\begin{gathered} \angle B=\angle C \\ (9x-73)=(3x+23) \\ 9x-73-3x-23=0 \\ 6x-96 \end{gathered}[/tex]So,
[tex]\begin{gathered} 6x-96=0 \\ 6x=96 \\ x=\frac{96}{6} \\ =16 \end{gathered}[/tex]Then,
For the measure first angle;
So,
Put the value of x in given angle,
[tex]\begin{gathered} m\angle ABC=(9x-73)^{\circ} \\ =(9\times16-73) \\ =71^{\circ} \end{gathered}[/tex]Hence, the value of x is 16 and the measure of the first base angleangle is 71 degree.