Data:
Binder: b
Notebooks: n
pens adn pencils: p
Cost: C
Amount $: T
b=1
n=5
T= $40
Cb=$12.50
Cn=$3.25
Cp=$2.50
As Laurtn have $40, this amount needs to be equal to the add to the cost of each item
[tex]\begin{gathered} T=b(C_b)+n(C_n)+p(C_p)_{} \\ \\ 40=1(12.50)+5(3.25)+p(2.50) \\ \\ 40=12.50+16.25+2.50p \\ \\ 40=28.75+2.50p \\ \end{gathered}[/tex]To find the number of packs of pen and pencils can she purcase you solve for p:
[tex]\begin{gathered} 40=28.75+2.50p \\ 40-28.75=2.50p \\ 11.25=2.50p \\ \frac{11.25}{2.50}=p \\ 4.5=p \end{gathered}[/tex]Then, she can purchase 4.5 packs of pens and pencils.Yes, she can purchase 3 packsNo, she cannot purchase 6 packs-------------------------------------------b=2
n=6
p=2
[tex]\begin{gathered} T=b(C_b)+n(C_n)+p(C_p)_{} \\ \\ T=2(12.50)+6(3.25)+2(2.50)= \\ T=25+19.5+5 \\ T=49.5 \end{gathered}[/tex]No, the budget of Laundry c