Respuesta :

The general equation of the circle is :

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where r is the radius of the circle

And ( h , k ) is the center of the circle

Given the equation :

[tex](x+1)^2+(y-1)^2=4[/tex]

making the given equation like the general form :

[tex](x-(-1))^2+(y-1)^2=2^2[/tex]

So, by comparing the equations :

[tex]\begin{gathered} h=-1 \\ k=1 \\ r=2 \end{gathered}[/tex]

So, the center of the circle = ( h , k ) = ( -1 , 1 )

And the radius of the circle = r = 2

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