The general equation of the circle is :
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where r is the radius of the circle
And ( h , k ) is the center of the circle
Given the equation :
[tex](x+1)^2+(y-1)^2=4[/tex]making the given equation like the general form :
[tex](x-(-1))^2+(y-1)^2=2^2[/tex]So, by comparing the equations :
[tex]\begin{gathered} h=-1 \\ k=1 \\ r=2 \end{gathered}[/tex]So, the center of the circle = ( h , k ) = ( -1 , 1 )
And the radius of the circle = r = 2