In solving this question, we will solve both equations A and equation B and analyze what their solution will be:
Equation A:
[tex]\begin{gathered} 3(2x-5)=6x-15 \\ 6x-15=6x-15 \\ -15=-15 \\ \text{Since the left-hand side of the equation is equal to the right-hand} \\ \text{side, equation A has an infinite number of solutions.} \end{gathered}[/tex]Equation B:
[tex]\begin{gathered} 2+3x=3x-4 \\ 2=-4 \\ Since\text{ left-hand side is not equal to the right-hand side, equation B has} \\ no\text{ solution.} \\ \\ \text{The correct answer is the second option.} \end{gathered}[/tex]