Question

Find f(t – 3) for f(x) = 4x² – 8x + 4. 1) 4t² – 32t + 642) 643) 4t² – 32t – 644) 4t² + 32t + 64

Answer 1

We have got the function:

$f(x)=4x^2-8x+4$

If we want to calculate:

$f(t-3)$

We can simply substitute every "x" in the function with "t-3". We need to use parenthesis when we do that:

$f(t-3)=4(t-3)^2-8(t-3)+4$

To get an answer that corresponds to one of the alternatives, we will need to simplify. First, let's solve the square and the parenthesis:

$\begin{gathered} f(t-3)=4(t^2-6t+9)-8t+24+4 \\ f(t-3)=4t^2-24t+36-8t+28 \\ f(t-3)=4t^2-32t+64 \end{gathered}$

This corresponds to alternative 1.