Answer
The pressure change = 3.11 atm
Explanation
Given:
Initial pressure, P₁ = 3.00 atm
Initial temperature, T₁ = 25.0 °C = (25.0 + 273.15 K) = 298.15 K
Final temperature, T₂ = 36.0 °C = (36.0 + 273.15 K) = 309.15 K
What to find:
The final pressure, P₂.
Step-by-step solution:
The final pressure, P₂ of the gas can be calculated using the Amonton's law equation/formula given below:
[tex]\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \\ \Rightarrow P_2=\frac{P_1T_2}{T_1} \end{gathered}[/tex]Putting the values of the parameters into the formula, we have:
[tex]P_2=\frac{3.00\text{ }atm\times309.15\text{ }K}{298.15\text{ }K}=3.11\text{ }atm[/tex]Therefore, the pressure change when a constant volume of gas at
3.00 atm is heated from 25.0 °C to 36.0 °C = 3.11 atm.
