Answer
V2 = 738.57 mL
Explanation
Given
Volume 1 = 735 mL
Pressure 1 = 1.20 atm
Temperature 1 = 112 ∘C = 385 K
Pressure 2 = 648 mmHg = 0.853 atm
Temperature 2 = 275 K
Required: Volume 2 in mL
Solution:
Use a combined gas law
[tex]\frac{P_1V_1}{T_1}\text{ =}\frac{P_2V_2}{T_2}[/tex]V2 = (P1V1T2)/T1P2
V2 = (1.20 x 735 x 275)/(385 x 0.853)
V2 = 738.57 mL