Respuesta :

For:

[tex]\begin{gathered} y\le-2x-2 \\ x=1;y\le-4 \\ x=-1;y\le0 \\ x=0;y\le-2 \end{gathered}[/tex]

For:

[tex]\begin{gathered} y\ge x+2 \\ x=0;y\ge2 \\ x=-1;y\ge1 \\ x=1;y\ge3 \end{gathered}[/tex]

Now, the solution of the system is given by:

[tex]\begin{gathered} x<-\frac{4}{3},x+2\le y\le-2(x+1) \\ x=-\frac{4}{3},y=\frac{2}{3} \end{gathered}[/tex]

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