Question

Use the remainder theorem to find P(-1) for P(x) = -x³-3x² - 4x +3. Specifically, give the quotient and the remainder for the associated division and the value of P(-1). Quotient = Remainder= p(-1)=

Answer 1

Solution:

Given the polynomial;

$P(x)=-x^3-3x^2-4x+3$

Using synthetic division;

Thus, the quotient is;

$quotient=-x^2-2x-2$

The remainder is;

$Remainder=5$

Also;

$\begin{gathered} P(-1)=-(-1)^3-3(-1)^2-4(-1)+3 \\ \\ P(-1)=5 \end{gathered}$