Given data:
* The mass of the Mangan is 86 kg.
* The friction force applied by the floor on the Mangan is 150 N.
Solution:
The normal force acting on the Mangan is,
[tex]F_N=mg[/tex]where m is the mass of Mangan, and g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} F_N=86\times9.8 \\ F_N=842.8\text{ N} \end{gathered}[/tex]The friction force acting on the Mangan is,
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