The mass of the truck is M = 3000 kg and the initial speed of the truck is u = 28 m/s.
After traveling through the rainstorm, the mass of the water is m = 500 kg is collected in the truck, the final mass will be m+M = 3500 kg and the final speed of the truck is v = 24 m/s.
The momentum is conserved if initial momentum = final momentum
On substituting the values,
[tex]\begin{gathered} Initial\text{ momentum =Mu} \\ =3000\times28 \\ =84000\text{ kg m/s} \\ F\text{inal momentum = (m+M)v} \\ =3500\times24 \\ =84000\text{ kg m/s} \end{gathered}[/tex]Thus, the momentum is conserved.
