ANSWER:
14.14 N, 45° (northeast)
STEP-BY-STEP EXPLANATION:
We can represent the problem as follows:
We calculate the net force as follows:
[tex]\begin{gathered} F_N=\sqrt[]{F^2_{up}+F^2_{right}} \\ \text{ replaicng} \\ F_N=\sqrt[]{10^2+10^2} \\ F_N=\sqrt[]{100+100} \\ F_N=\sqrt[]{200}=14.14\text{ N} \end{gathered}[/tex]
Therefore, the resultant force is 14.14 N with a direction of 45°
