Question

what is the answer of this problem ? help me to find

Answer 1

Given:

Total invested amount = $9000

One account = 5%

Another account = 6%

Find-:

Invested amount of each equation

Explanation-:

Let in 5% account invested amount is x

then amount in 6% account is (9000-x)

Then,

$5\%\text{ of }x+6\%\text{ of }(9000-x)=510$

Then the value of "x" is:

$\begin{gathered} \frac{5}{100}\times x+\frac{6}{100}\times(9000-x)=510 \\ \\ 0.05x+0.06(9000-x)=510 \\ \\ 0.05x+(0.06\times9000)-0.06x=510 \end{gathered}$

The "x" is:

$\begin{gathered} 0.05x-0.06x+540=510 \\ \\ -0.01x=510-540 \\ \\ -0.01x=-30 \\ \\ x=\frac{-30}{-0.01} \\ \\ x=3000 \end{gathered}$

The value of x is 3000 the mean amount in 5% invested amount is 3000.

6% invested amount is:

$\begin{gathered} =9000-3000 \\ \\ =6000 \end{gathered}$

So each account invested amount is:

$\begin{gathered} 5\%\rightarrow3000 \\ \\ 6\%\rightarrow6000 \end{gathered}$