the following reaction, how many atoms of carbon monoxide is required to produce 26.4 g ofCH¿OH? (4 pts)CO + 2H, -> CHOH

The atoms of carbon monoxide that is required is 4.96 * 10^23 atoms
The balanced chemical reaction between carbon monoxide and hydrogen is given as:
[tex]CO+2H_2\rightarrow CH_3OH[/tex]Determine the mole of CH3OH
[tex]\begin{gathered} mole\text{ of CH}_3OH=\frac{mass}{molar\text{ mass}} \\ mole\text{ of CH}_3OH=\frac{26.4}{32.04} \\ mole\text{ of CH}_3OH=0.824moles \end{gathered}[/tex]From the given stoichiometry ratio, 1mole of CO produces 1 mole of CH3OH, the moles of carbon monoxide required will be 0.824moles
Determine the atoms of carbon monoxide required
According to Avogadro's constant;
1 mole of CO = 6.02 * 10^23 atoms
0.824 moles of CO = 0.824 * 6.02 * 10^23
0.824 moles of CO = 4.96 * 10^23 atoms
Hence the atoms of carbon monoxide that is required is 4.96 * 10^23 atoms