Question

hey please help. this has to do with exponential functions. i have to do 225 problems before midnight. it’ll mean a lot!!!

Answer 1

Answer:

Explanation:

To complete the missing values, we have to evaluate the function at the x-values given.

For example, to find the number below x = -1, we will put in x = -1 into y = (1/6)^x.

Putting in x = - 1 in y = (1/6)^x gives

$y=(\frac{1}{6})^{-1}$

which simplifies to give

$y=\frac{1}{1/6}$$\rightarrow y=6$

Similarly, for the missing value below x = -2, we put in x = - 2 into y = (1/6)^x to get

$y=(\frac{1}{6})^{-2}$

which simplifies to give

$y=\frac{1}{(1/6)^2}$$\begin{gathered} \rightarrow y=6^2 \\ \rightarrow y=36 \end{gathered}$

Similarly, for the missing value below x = 2, we put in x = 2 in y = (1/6)^x to get

$y=(\frac{1}{6})^2$

which simplifies to give

$y=\frac{1}{36}$

Hence, the missing value to be put in is 36.

To summerise, the missing values are

x | -2