Question

Hello I need help please.The choices for f(-6): A. f(-6) ; B. The answer is not a real number

Answer 1

Given the function:

$f\mleft(x\mright)=\sqrt{x-1}$

First part:

You need to substitute the following value of "x" into the function:

$x=1$

In order to find:

$f(1)$

Then, substituting and evaluating, you get:

$\begin{gathered} f(1)=\sqrt[]{1-1} \\ f(1)=\sqrt[]{0} \\ f(1)=0 \end{gathered}$

Second part:

Substitute this value of "x" into the function:

$x=-6$

And then evaluate, in order to find:

$f(-6)$

You get:

$\begin{gathered} f(-6)=\sqrt[]{-6-1} \\ f(-6)=\sqrt[]{-7} \end{gathered}$

Since the Radicand is negative, it is not a Real Number.

Therefore, the answers are:

First part:

A.

$f(1)=0$

Second part:

B. The answer is not a real number.