The rule of signs in binomial factors given a trinomial in the form :
[tex]x^2\pm bx\pm c[/tex]Note that b and c can be positive or negative.
And the factor may be :
[tex](x\pm m)(x\pm n)[/tex]First thing to do is to check the sign of c.
If it is positive, the signs of m and n can be both positive or both negative.
Since positive multiplied by positive is positive and
negative multiplied by negative is also positive.
[tex]\begin{gathered} (+)\times(+)=+ \\ (-)\times(-)=+ \end{gathered}[/tex]If the sign of c is negative, one of the factors must be negative and the other must be positive, because negative multiplied by positive is negative.
[tex](-)\times(+)=-[/tex]After considering the sign of c, next to check is the sign of b.
Case 1 :
If b and c are both positive, we know that the factors can be both negative or both positive.
And since the sign of b is positive, we must follow the sign of it which is positive.
So both m and n are positive
For example :
[tex]x^2+5x+6[/tex]The factor will be :
[tex](x+2)(x+3)[/tex]which are both positive.
Case 2 :
If b is negative and c is positive, we will follow the sign of b. m and n will be both negative.
For example :
[tex]x^2-5x+6[/tex]The factors are :
[tex](x-2)(x-3)[/tex]which are both negative
Case 3 :
Now the third case is tricky.
If c is negative, we know that one of m and n is negative and the other one is positive.
The sign of the larger number between m and n will follow the sign of b.
For example :
[tex]x^2-x-6[/tex]c is negative, so one factor must be negative and the other must be positive. The sign of b is negative, so the larger factor must be negative also.
The factor will be :
[tex](x-3)(x+2)[/tex]3 is larger than 2, so the negative sign of b will proceed to the factor 3.