Respuesta :

Using the sum-to-product identity:

[tex]\sin A-\sin B=2\cos (\frac{A+B}{2})\sin (\frac{A-B}{2})[/tex]

we can replace our expression and solve, where A = x and B = 5x:

[tex]\sin (x)-\sin (5x)=2\cos (\frac{x+5x}{2})\sin (\frac{x-5x}{2})[/tex]

Simplifying:

[tex]\sin (x)-\sin (5x)=2\cos (\frac{6x}{2})\sin (\frac{-4x}{2})[/tex][tex]\sin (x)-\sin (5x)=2\cos (3x)\sin (-2x)[/tex]

Answer:

[tex]=2\cos (3x)\sin (-2x)[/tex]

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