Question

a mixture of hydrocarbons contains 31.7% octane, c8h18, 12.0% heptane, c7h16, and 56.3% decane, c10h22. the mixture is combusted in an excess of oxygen. what mass of co2 is generated from the combustion of 13.7 kg of the mixture?

Answer 1

The mass of carbon dioxide formed on burning of Octane, heptane and decane is 47.79 Kg.

The total mass of the mixture is 13.7 kg.

Percentage of octane, heptane and decane in the mixture is 31.7%, 12% and 56.3%.

So,

Mass of octane in the mixture is,

Mass of octane = 13.7 × 32.7%

Mass of octane = 4479.9 g.

Molar mass of octane = 114 grams/mol

Moles of octane = 39.29 moles.

We know, one mole of octane produces 8 moles CO₂.

So, 39.29 moles of octane will produce 314.32 moles.

Mass of heptane in the mixture is,

Mass of heptane = 13.7 × 12%

Mass of heptane = 1644 grams

Molar mass of heptane = 100 grams/mol

Moles of heptane = 16.44 moles.

We know, one mole of heptane produces 7 moles CO₂.

so, 16.44 moles of heptane will produce 115.08 moles of CO₂

Mass of decane in the mixture is,

Mass of decane = 13.7 × 56.3%

Mass of decane = 7713.1 g.

Molar mass of decane = 142 grams/mol

Moles of decane = 54.31 moles.

We know, one mole of octane produces  10 moles CO₂.

So, 54.31 moles will produces 543.1 moles of CO₂.

So, the total moles of CO₂ produced are 543.1 + 115.08 + 314.32 moles.

The total moles of CO₂ produced are 972.5 moles.

We know,

Mole = formed mass/Molar mass

So,

Moles of CO₂ = 972.5

Molar mass of CO = 44g/mol

Formed mass of CO₂ = 972.5 x 44

Formed mass of CO₂ is 42790 grams.

Hence a total of 47.79 Kg of CO₂ is formed.

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